pywebpush_vapid_authenticated_push_notification_send.py

1from pywebpush import webpush, WebPushException
2
3import json
4
5# Subscription information obtained from the browser/frontend
6subscription_info = {
7    "endpoint": "https://updates.push.services.mozilla.com/wpush/v1/...",
8    "keys": {
9        "auth": "...",
10        "p256dh": "..."
11    }
12}
13
14# The message you want to send
15data = "Mary had a little lamb"
16
17# VAPID keys can be generated using 'vapid-utils' or other tools
18# This should be your private key
19VAPID_PRIVATE_KEY = "./private_key.pem"
20VAPID_CLAIMS = {
21    "sub": "mailto:admin@example.com"
22}
23
24try:
25    response = webpush(
26        subscription_info=subscription_info,
27        data=data,
28        vapid_private_key=VAPID_PRIVATE_KEY,
29        vapid_claims=VAPID_CLAIMS
30    )
31    print("Push sent successfully")
32except WebPushException as ex:
33    print("Web Push Error: {}".format(repr(ex)))
34    # data will be a dict in some cases, e.g. if the notify endpoint is unavailable
35    if ex.response and ex.response.json():
36        extra = ex.response.json()
37        print("Remote service replied with a {}:{}, {} ".format(
38            extra.get('code'),
39            extra.get('errno'),
40            extra.get('message')
41        ))