cloudpathlib_s3_file_access_with_pathlib_api.py

1from cloudpathlib import CloudPath
2
3# Create a CloudPath object (supports s3://, gs://, or az://)
4# This example uses a public S3 bucket
5cp = CloudPath("s3://covid19-lake/rearc-usa-hospital-beds/json/metadata/metadata.json")
6
7# Basic metadata
8print(cp.name)
9# metadata.json
10
11print(cp.stem)
12# metadata
13
14print(cp.suffix)
15# .json
16
17# Check if file exists
18print(cp.exists())
19# True
20
21# Read content directly from cloud
22with cp.open("r") as f:
23    content = f.read()
24    print(content[:50])