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django_waffle_feature_flag_conditional_view_quickstart.py

python

Demonstrates how to use a feature flag in a Django view to conditionally e

15d ago8 linesdjango-waffle.readthedocs.io
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django_waffle_feature_flag_conditional_view_quickstart.py
1import waffle
2from django.http import HttpResponse
3
4def my_view(request):
5    if waffle.flag_is_active(request, 'my_flag'):
6        return HttpResponse("The flag is active!")
7    else:
8        return HttpResponse("The flag is not active.")