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sparqlwrapper_dbpedia_query_with_json_results.py

python

An example of how to query a SPARQL endpoint and get the results as JSON.

15d ago13 linesrdflib.dev
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sparqlwrapper_dbpedia_query_with_json_results.py
1from SPARQLWrapper import SPARQLWrapper, JSON
2
3sparql = SPARQLWrapper("http://dbpedia.org/sparql")
4sparql.setQuery("""
5    PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
6    SELECT ?label
7    WHERE { <http://dbpedia.org/resource/Asturias> rdfs:label ?label }
8""")
9sparql.setReturnFormat(JSON)
10results = sparql.query().convert()
11
12for result in results["results"]["bindings"]:
13    print(result["label"]["value"])