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bugsnag_quickstart_configure_api_key_and_notify_exception.py

python

Configures Bugsnag with an API key and demonstrates how to manually notify the s

15d ago13 linesdocs.bugsnag.com
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bugsnag_quickstart_configure_api_key_and_notify_exception.py
1import bugsnag
2
3# Configure Bugsnag with your API key
4bugsnag.configure(
5    api_key="YOUR_API_KEY_HERE",
6    project_root="/path/to/your/project",
7)
8
9# You can now notify Bugsnag of an exception manually
10try:
11    raise Exception("Something went wrong!")
12except Exception as e:
13    bugsnag.notify(e)