django_object_actions_custom_admin_button_quickstart.py

1from django.contrib import admin
2from django_object_actions import DjangoObjectActions
3
4
5class MyModelAdmin(DjangoObjectActions, admin.ModelAdmin):
6    def publish_this(self, request, obj):
7        obj.publish()
8    
9    publish_this.label = "Publish"  # Optional
10    publish_this.short_description = "Submit this object"  # Optional
11
12    change_actions = ('publish_this', )